What is the minimum frequency of light necessary to emit electrons from titanium via the photoelectric effect?

1.05 × 10 ∧15 Hz.

Explanation:

The minimum amount of energy of photon E = 6.94×10∧-19  J

The value of Plank's constant , h = 6.626 × 10∧-34 J s

So the minimum frequency of light necessary to emit electrons from titanium via photoelectric effect , E = h . ν

where ν is the frequency

                                       ν = E / h

                                       ν = 6.94×10∧-19  J / 6.626 × 10∧-34 J s

                                         = 1.05 × 10 ∧15 / s

                                         = 1.05 × 10 ∧15 Hz.

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop