Arturo and Bianca are discussing the speeds of cars A and B. Arturo says: It looks like when the time is exactly 1.0s, the speed of Car B is greater than the speed of Car A. Bianca says: It also looks to me like the speed of Cars A and B are exactly the same at about 2.0s. Do you agree or disagree with Arturo and Bianca

he two people agree with your answer

  v_B = v_{oB} - a t

              v_A = cte

Explanation:

To analyze if they are both in Kurdish, let's see the movement of the two cars

at t = 1s

the velocity of carriage B is greater than the speed of carriage a

             v_B> v_A

at t = 2 s

the speed of the two cars is nipple

              v_B = v_A

For this to be true, the speed of car B must be decreasing

              v_B = v_{oB} - a t

              v_A = cte

therefore the two people agree with your answer

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me