Physics, 19.02.2021 03:00 mqturner1989Kedie
Two cars are moving in the same direction. One car with momentum p1 collides with another, which has momentum p2. Their momenta become p′1 and p′2 respectively. Considering frictional losses, compare (p′1+p′2) with (p1+p2).
a) The value of (p′1+p′2) is zero.
b) The values of (p1+p2) and (p′1+p′2) are equal.
c) The value of (p1+p2) will be greater than (p′1+p′2).
d) The value of (p′1+p′2) will be greater than (p1+p2).
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