Player 41 hits a hard line drive. Player 6 waits at the starting gate in a runner's position.

Player 6 sprints from the starting gate in the 100-meter run.

Player 10 hits the golf ball with his club.

The pitcher stands with his arm above his head and the bat in his hand.

Player 32 backhands the ball which zooms across the court.

Player 22 steps off the platform plunging rapidly downward.

Potential or kinetic energy

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s