A stalled car is pushed with a force of 342 N from rest. How far does the car travel in 12 seconds if its mass is 989 kg? ​

Roughly 25 meters

Explanation:

Use the formula D=1/2*a*t^2 where d=distance, a=acceleration, and t=time

Plug in all the variables we know...

D=1/2*a*12^2

in order to solve for acceleration, we use the formula  F=ma where F=force, m=mass, and a=acceleration.

Plug in known variables,

342N=989kg*a

solve for a and we get...

342N/989kg=a

Now that we know the acceleration, we can plug that into our original equation and solve for distance.

D=1/2*342N/989kg*12s^2

Simplify,

D=72s^2*342N/989kg

D=72s^2*342kgm/s^2/989kg

D=72s^2*342m/s^2/989

D=72*342m/989

D=24624/989 meters, or 24.898meters which rounds up to 25.

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explanation: