Extra credit!! Find the total power of the following circuit.

R1=10 ohms and R2=10 ohms are connected in parallel with each other, but they are both in series with R3= 5 ohms. The battery has a voltage of 80 v.

the correct answer is b

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j