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Physics, 12.02.2021 21:50 diflakf

The force F = (6.76 N)i + (4.2 N)j acts on a particle as it moves first along the x axis from x = 3.33 m to x = 7.32 m, then parallel to the y axis from y = 2.56 m to y = 9.12 m. What is the work done, in joules, by the force?

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The force F = (6.76 N)i + (4.2 N)j acts on a particle as it moves first along the x axis from x = 3....

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