Help pls There are two groups of students participating in a tug of war. One group pulling two the east is pulling with a force of 5,000N. It is a stalemate and there is no movement. What is the force of the group pulling to the west and what is the net force?

a. 7000 N, 2000N west
b. 6000 N, 1000N west
c. 4000N, 1000 N east
d. 3000N, 2000 N west
e. 5000 N, 0N

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

the answer is b i think

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft