PE = mgh gravity=g= 10 m/s/s I almost hit the ground but luckily I snap back up towards the
top of the building. What was my potential energy just before
hitting the ground?

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west