You walk in a straight line for 95 m at an angle of 162° above the positive x axis. What are the x and y components of your displacement?

Explanation:

{ r, θ ) = [ r cosθ i , r sinθ j ]

( 95m , 162°) = [ 95 cos 162 i, 95 sin 162 j]

( 95m , 162°) = [ 95 * -0.951 i, 95 * 0.309 j]

( 95m , 162°) = -90.342 i, 29.355 j =

[ -90.34 m i , 29.36 m j ]

Therefore, the displacement of x and u components are

x displacement = -90.35 m and y displacement = 29.36 m

round appropriately

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft