Suzy, Marie, Gabby, and Veronica are playing football in the park. Both Marie and Gabby go for the interception and crash into each other! If their total momentum is 382 kg. m/s after the collision and Marie's momentum is 180 kg . m/s before the collision, what is Gabby's momentum before the collision?

Gabby's momentum before the collision is 202 kg·m/s

Explanation:

The given parameters of the motion of the people playing football in the park are;

The interaction of Marie and Gabby when they go for the interception = Collide

The total momentum of Marie ang Gabby after the collision, = 382 kg·m/s

The initial momentum of Marie, P₁ = 180 kg·m/s

By the law conservation of conservation of linear momentum, we have;

The total initial momentum before the collision, = The total momentum after the collision,

The total initial momentum before the collision, = Marie's momentum before the collision, P₁ + Gabby's momentum before the collision, P₂

∴ = P₁ + P₂ = 180 kg·m/s + P₂

From which we have;

= 180 kg·m/s + P₂ = = 382 kg·m/s

∴ 180 kg·m/s + P₂ = 382 kg·m/s

P₂ = 382 kg·m/s - 180 kg·m/s = 202 kg·m/s

P₂ = 202 kg·m/s

Gabby's momentum before the collision, P₂ = 202 kg·m/s.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day