Superman does an exhibition run at a track meet. When he runs the 200 m dash, he accelerates at 10 m/s/s for the entire distance. Approximately
how much time will it take him to run the 200 m? *

6.32s

Explanation:

Given parameters:

Length of track and distance covered  = 200m

Acceleration  = 10m/s²

Unknown:

Time taken to cover the track  = ?

Solution:

To solve this problem, we apply one of the motion equations as shown below:

       S  = ut + at²  

S is the distance covered

t is the time taken

a the acceleration

u is the initial velocity

The initial velocity of Superman is 0;

 So;

     S  =   at²  

        200  =   x 10 x t²  

          200  = 5t²  

            t²  = 40

            t  = 6.32s

the body's situation won't change the forces are equal opposit and on the same body

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)