How fast will a runner be going in he accelerated from year at 30 m/s^2 for a distance of 2.5 m?

Vf =3.87[m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (from the rest)

a = acceleration = 3 [m/s²]

x = distance = 2.5 [m]

Now replacing:

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

probably not if net force is zero