A projectile is launched with an initial velocity 60m/s at an angle 60° to the vertical. What the magnitude of it's displacement after 5s.

the magnitude of the displacement after 5s is 137.31 m.

Explanation:

Given;

initial velocity of the projectile, u = 60 m/s

angle of projection, θ = 60°

time of motion, t = 5s

the vertical component of the velocity,

The magnitude of the displacement after 5s is calculated as;

Therefore, the magnitude of the displacement after 5s is 137.31 m.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by