TEKS P.6A 6. How much gravitational potential energy do you think a 75-kilogram diver would have
stepping off the edge of a 5-meter platform?
F. 15 )
G. 147 J
H. 375 J
J.3675 J
TEKS P.6A

If its history of, then b) because a) implies only present day (now)

The correct answer should be b let me know if i’m wrong

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.