You took a running leap off a high diving platform. you were running at 2.8m/s and hit the water 2.6 seconds later. how high was the platform, and how far from the edge of the platform did you hit the water? assume your initial velocity is horizontal. ignore air resistance.

Thank you for posting your question here at . Below is the solution:

 Initial values: 

vox = 2.9 m/s (assume that you begin horizontally) 
voy = 0 m/s 
ax = 0 m/s^2 
ay = -9.8 m/s^2 
t = 2.6 s 
xo = 0 
y = 0 

First of all, we are finding yo, or the height. We can use the following kinematics equation: y = yo + voy*t + .5*ay*t^2 

Solve for yo, cancel 0 values: -yo = .5*ay*t^2 

Plug in values: -yo = .5 * -9.8 * 2.6^2 

yo = height = 33.124 meters 

After that, we are to find the horizontal range, or x. We can use the following kinematics equation: x = xo + vox*t + .5*ax*t^2 

Cancel 0 values: x = vox*t 

Plug in values: x = 2.9 * 2.6 

x = horizontal range = 7.54 meters

By dividing you can find the answer