A bug starts out at rest, 3 m to the right of the origin. It then starts moving on a trip. After 1 s, the bug is seen at 9 m to the right of the origin, travelling at 5 m/s to the right. After 7 s (from the start of the trip), the bug is seen at 2 m to the left of the origin, travelling at 8 m/s to the right. a.) What is the position vector of the bug 1 s after the start of the trip

       d = 6 i^   m

Explanation:

This is an exercise in kinematics, where the position vector is the displacement of the body from one point to another.

In this case we are told that for t = 0 the worm is at x₀ = 3m and with velocity starts from zero, after t = 1 s it is at x₁ = 9m and with a velocity of

v₁ = 5 m / s

They ask what is the displacement for the time of 1 s

               d = x₁ - x₀

               d = 9 -3 m

               d = 6 m

Bold indicates vector, displacement vector is

             d = 6 i ^ m

1 the 4 is sig

yo yo yo its papaguy in the house lol

okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?