What is the stretch when you pull with a force of 2.3 N on a spring with a spring constant of 19 N/m?

x=0.12 m

Explanation:

Use the equation F=kx and isolate x because that's what you're solving for (x=F/k). Plug in your given values for F and k and solve for x [x=(2.3 N)/(19 N/m)] and you get x=0.12 m.

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