How much force did the puck experience to attain this acceleration? And what is the weight of the puck? Acceleration = 33.2 m/s/s

Useful Information:

F = ma

F sub g = mg where g is 9.8 m/s^2

F sub g means gravitational force

mass of the hockey puck = 169.7 g = 0.1697 kg

mass of the regulation composite hockey stick = 737 g = 0.737 kg

For example, if F = 100 N, T = 0.04 s and m = 0.17 kg, then a = 588 m/s2 and v = 23.5 m/s. Given that the acceleration to to gravity is 9.8 m/s2, the acceleration of a puck is huge by comparison. A higher puck speed will result if the force on the puck is increased or if the force is applied for a longer time.

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂