While being thrown, a net force of 132 N acts on a baseball (mass = 140g) for a period of 4.5 x 10-2 sec. [Hint: Convert mass to kg]

A.) What is the magnitude of the change in momentum of the ball?

B.) If the initial speed of the baseball is vi=0.0 m/s, what will it’s speed be when it leaves the pitchers hand?

C.) When the batter hits the ball, a net force of 1320 N, opposite to direction of the balls initial motion, acts on the ball for 9.0x10^-3 seconds during the hit. What is the change in momentum of the ball?

D.) What is the final velocity of the ball?

E.) What force does the ball exert on the bat in the question above? Explain.

Answerapply an acl that has all deny ace statement;

The density of the block of iron is lees than the density of mercury but the density of the block of iron is greater than the density of water

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)