Lots of points! Will mark brainliest!! 1. How much force will be needed to move a 110kg box across the floor if the coefficient of friction is
0.40?
2. If the coefficient of friction is lowered to 0.25, but the same amount of force was applied, what would the acceleration of the object in problem #1 be?

1. 431.2newtons

2. 1.47meters per second squared

Explanation:

f=ma

force of friction=normal force×coefficient of friction

normal force = mass× gravity

1.

nf=110kg × 9.8m/s^2 = 1078newtons

f=nf×cf

f=1078×.4=431.2

1

f=1078×.25=269.5

431.2-269.5=161.7

161.7=110kg× a

a=1.47

! 55 !  

write a paragraph or story to explain the transformation between potential and kinetic energy as shown in your picture or model.  

you should have at least 5 complete sentences with a main idea and supporting details.  

you must include the following words:  

potential energy

kinetic energy

mechanical energy

conservation of energy

dude, this is hard lol : ))