PLEASE HELP❤️❤️❤️❤️ 1. A spring extends by 20 cm when a force of 2 N is applied. What is the value of the spring constant in N/m?
2. A spring extends by 5 cm when a force of 20 N is applied to it. What force would be needed to extend the
spring by 10 cm?

1. 10 N/m

2. 40 N

Explanation:

1. Determination of the spring constant.

We'll begin by converting 20 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

20 cm = 20 cm × 1 m / 100 cm

20 cm = 0.2 m

Finally, we shall determine the spring constant. This can be obtained as follow:

Extention (e) = 0.2 m

Force (F) = 2 N

Spring constant (K) =?

F = Ke

2 = K × 0.2

Divide both side by 0.2

K = 2/0.2

K = 10 N/m

Thus, the spring constant is 10 N/m

2. Determination of the force.

Initial extention (e₁) = 5 cm

Initial force (F₁) = 20 N

Final extension (e₂) = 10 cm

Final force (F₂) =?

F = Ke

Divide both side by e

K = F /e

Therefore,

F₁ /e₁ = F₂/e₂

20/5 = F₂/10

4 = F₂/10

Cross multiply

F₂ = 4 × 10

F₂ = 40 N

Thus, a force of 40 N is needed to stretch the spring by 10 cm.

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.