A 15.0 kg bowling ball rolling at 3 m/s is stopped by a constant force of 11.2 newtons. Calculate the time the force must act on the bowling ball to stop it.

4.01 seconds

Explanation:

Given that:

Mass of ball = 15kg

Initial velocity, u = 3m/s

Final velocity, v = 0

Force, F= 11.2 N

Change in velocity, dv = 3 - 0 = 3

Time force must act on the ball before stopping it:

Using the relation :

F = ma

a = (v - u) / t

Ft = m(v - u)

11.2 * t = 15 * 3

11.2t = 45

11.2t = 45

t = -+¯ 45 / 11.2

t = 4.01

t = 4 seconds.

the answer would be 32*f

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