an object on a number like moved from x = 12 m to x = 124 m and moved back to x = 98 m. the time interval for all the motion was 10 s. what was the average velocity of the object?

Complete Question:

an object on a number line moved from x = 12 m to x = 124 m and moved back to x = 98 m. the time interval for all the motion was 10 s. what was the average velocity of the object?

v = 8.6 m/s

Explanation:

By definition, the average velocity, is just the rate of change of the position (denoted by the x-coordinate in this case) with respect to time, as follows:

       

This means that the average velocity depends only on the final and initial positions, independent from the intermediate points between them.As we can choose freely our origin in time, we choose the initial time to be zero.At that time, the x-coordinate is x=12 m, so x₀ = 12 m.When t= 10.0 s, x is 98 m, so xf = 98 m.Replacing in (1) we get: