A car accidently volls of f a cliff a is leaves the cliff has a horzontal velocity of 13m/s if hits the ground 6am from the share line calculate the heigh of the cliff

Complete question :

A car accident my rolls off a cliff as it leaves the cliff it has a horizontal velocity of 13 ms it hits the ground 60 m from the shoreline calculate the height of the cliff

104.59 m

Explanation:

Given that:

Horizontal Velocity = 13 m/s

Horizontal distance = 60 m

To obtain the height of the cliff :

We use the Relation :

S = ut + 0.5at²

t = time ; u = initial velocity ; S = height

To obtain t ;

Speed = distance / time

Horizontal distance / speed = time

Time = 60 / 13

Time = 4.62 seconds

The height of cliff :

u = 0

Hence ;

S = ut + 0.5at²

S = 0 + 0.5(9.8) * 4.62^2

S = 104.58756

Height of cliff = 104.59 m

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm