If a certain shade of blue has a frequency of 7.33 x 10^14hz, what is the energy of exactly one photon of this light?
is this as simple as multiplying the frequency by planck's constant?

The best way to express this is by means if this formula: E = h v. H is the plancks constant and v is the frequency. The procedure will look like this:
E = 6.626 x 10-34 J s (7.33 x 10^14 /s) = 4.857 x 10^-19 J
That is how we may express the energy. And as you can see, you can solve it with the plancks constant and multiplying the frequency

The purpose of a lab is to do your "expirements" the importance of the topic is so you can now what the story is about and the last one is because no one is me with my question ( what is 3 over 4 x - 9 = 27 maybe you can )