1. Calculate the heat capacity of a piece of wood if 1500.0 g of the wood absorbs 6.750.000 joules of heat, and its temperature changes from 32°C to 57°C.

1.8 J/gºC

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature of the wood. This can be obtained as follow:

Initial temperature (T₁) = 32 °C

Final temperature (T₂) = 57 °C

Change in temperature (ΔT) =.?

ΔT = T₂ – T₁

ΔT = 57 – 32

ΔT = 25 °C

Finally, we shall determine the heat capacity of the wood. This can be obtained as follow:

Mass (M) = 1500 g

Heat (Q) absorbed = 67500 J

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) =?

Q = MCΔT

67500 = 1500 × C × 25

67500 = 37500 × C

Divide both side by 37500

C = 67500 / 37500

C = 1.8 J/gºC

Thus, the heat capacity of the wood is 1.8 J/gºC

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

mass and volume are the answers you are looking for