In the picture above, if the cue stick strikes the 0.2-kg cue ball with a force of 1.1 N, what will be the acceleration of the cue ball?

0.55 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of ball = 2 Kg

Force (F) applied = 1.1 N

Acceleration (a) =?

Force (F) is defined as the product of mass (m) and acceleration (a). Mathematically, the force (F) can be represented as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can calculate the acceleration of the ball as follow:

Mass (m) of ball = 2 Kg

Force (F) applied = 1.1 N

Acceleration (a) =?

F = ma

1.1 = 2 × a

Divide both side by 2

a = 1.1 / 2

a = 0.55 m/s²

Therefore, the acceleration of the ball is 0.55 m/s²