If the coefficient of static friction is 0.35 and the normal force is 80 newtons, what is the maximum frictional force of the surface acting on the object? A. 9.8 newtons B. 28 newtons C. 80 newtons D. 23 newtons E. 35 newtons

Option B. 28 N

Explanation:

From the question given above, the following data were obtained:

Coefficient of static friction (μ) = 0.35

Normal force (N) = 80 N

Frictional force (F) =?

The coefficient of static friction, frictional force and the normal force are related according to the following equation:

Coefficient of friction = frictional force / normal force

μ = F/N

With the above formula, we can obtain the frictional force as follow:

Coefficient of static friction (μ) = 0.35

Normal force (N) = 80 N

Frictional force (F) =?

μ = F/N

0.35 = F / 80

Cross multiply

F = 0.35 × 80

F = 28 N

Thus the frictional force is 28 N

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