Imagine a plane leaves Ronald Reagan airport and travels along vector A northeast towards Annapolis. When it reaches the city, the plane turns toward the northwest to reach Baltimore travelling over vector B. Next it turns back to the southwest, takes vector C to Dulles airport and returns home on vector D. Now imagine you start from the same position, but this time your first trip goes in the direction of vector B. Then you travel by vector C, D, and finally A. What is your destination this time

positive reinforcement? ?

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down