Consider a neutron star with a mass equal to the sun, a radius of 10 kmkm, and a rotation period of 1.0 ss. What is the speed of a point on the equator of the star

6.28 * 10⁴ m/s

Explanation:

Using the relation :

Given :

Radius, R = 10km

Period, T = 1.0 s

v = (2πR) / T

Where v = velocity of a point

R in meters ;

1km = 1000m = 10³m

10km = 10 * 10³m = 1 * 10^4 m

v = (2π*10^4m) / 1 s

v = 6.2831853 * 10⁴ m/s

v = 6.28 * 10⁴ m/s

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.