An ice-hockey player weighing 900 N is skating with a velocity of 8.0 m/s when they slam into a member of the opposing team who is standing still. They become tangled together and move down the ice with a velocity of 5.0 m/s. What is the mass of the other player

Mass of player 2 is 55.044kg

Explanation:

Step one:

given data

Weight of player 1= 900 N

mass= weight/acceleration due to gravity

mass of player= 900/9.81

m1= 91.74kg

v1= 8m/s

mass of player 2

m2= ?

v2= 0m/s

Step two:

from the problem description, after impact, they both moved with a common velocity of V= 5m/s, hence the collision is an inelastic collision

the expression for inelastic collision is

m1v1+m2v2=(m1+m2)V

substitute

91.74*8+m2*0=(91.74+m2)5

733.92=458.7+5m2

275.22=5m2

divide both sides by 5

m2=275.22/5

m2=55.044kg

The weight of player two is

=55.044*9.81

=539.98N

the arctic is a region of the planet, north of the arctic circle, and includes the arctic ocean, greenland, baffin island, other smaller northern islands, and the far northern parts of europe, russia (siberia), alaska and canada.

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )