If 100.0 g of a substance releases 45 kJ of energy as it cools from 13.0°C to –15.0°C, what is the specific heat capacity of the substance?

Explanation:

The formula for expressing the quantity of heat released is expressed as;

Q = mcΔt

m is the mass of the substance = 100g - 0.1kg

c is the specific heat capacity of the substance

Δt is the change in temperature = 13 -(-15) = 28°C

Substitute and get c;

45000 = 0.1c(28)

2.8c = 45000

c = 45000/2.8

c = 16,071.42J/kgK

Hence the specific heat capacity of the substance is 16,071.42J/kgK

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