1. During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +9.0 m/s at an angle of 35.0° find the following: a) How long will each stone be in the air assuming the stones land at the same level as they are launched? Show all work.
9sin35=5.162 m/s
9cos35=7.37 m/s
5.16/9.8=0.527s
0.527time 2= 1.054s in the air.

b) What is the maximum height of the launched stones? Show all work.
0.5times 9.8^2times 0.527^2 = 13.337
1.365m is the maximum height.

c) What is the range (horizontal distance) that the stone will travel? Show all work
7.77m

d) What is the velocity of each stone as it hits the ground?

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )