A 12.9 kg pelican, with a 1.51 kg fish in its mouth, is flying 14.94 m/s at a height of 114 m when the fish wiggles free and fall back toward the ocean. How fast is the fish moving when it hits the water

v =  49.6 m/s

Explanation:

The vertical component of the final speed can be found by using 3rd equation of motion:

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 114 m

Voy = vetical component of initial velocity = 0 m/s (since the pelican is flying horizontally)

Vy = Vertical component of final velocity = ?

Therefore,

Now, the horizontal component of the velocity is assumed to be the same because of negligible frictional force. Therefore,

Vx = 14.94 m/s

Thus the final speed will be given as:

v =  49.6 m/s

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

the bal will not change its velocity.