Suppose you walk 11.2 m straight west and then 27.3 m straight north. How far are you from your starting point

29.51m

Explanation:

Suppose you walk 11.2 m straight west and then 27.3 m straight north. How far are you from your starting point

Your distance from the starting point is your displacement

Using the pythagoras theorem

d² = (-11.2)²+(27.3)²

d² = 125.44+745.29

d² = 870.73

d = √870.73

d = 29.51m

Hence your distance from the starting point is 29.51m

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.