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$ 1.1

Explanation:

From the question given above, the following data were obtained:

Cost per kWh = $ 0.1

Current (I) = 10 A

Voltage (V) = 220 V

Time (t) = 5 h

Cost of operation =?

Next, we shall determine the power the electric oven. This can be obtained as follow:

Current (I) = 10 A

Voltage = 220 V

Power (P) =?

P = IV

P = 10 × 220

P = 2200 W

Next, we shall convert 2200 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

2200 W = 2200 W × 1 KW / 1000 W

2200 W = 2.2 KW

Thus, 2200 W is equivalent to 2.2 KW.

Next, we shall determine the energy consumed by the electric oven. This can be obtained as follow:

Power (P) = 2.2 KW

Time (t) = 5 h

Energy (E) =?

E = Pt

E = 2.2 × 5

E = 11 KWh

Finally, we shall determine the cost of operation. This can be obtained as follow:

1 KWh cost $ 0.1

Therefore,

11 KWh will cost = 11 × 0.1

11 KWh will cost = $ 1.1

Therefore, the cost of operating the electric oven is $ 1.1

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

need to see circuit to get time constant