A car is traveling at speed of 18.6m/s and entering a 12m wide intersection when the light has 0.582seconds More Time remain yellow. a) what does the acceleration of the car needed to be so that its infront is out of the intersection when the light turns red?

6.94 m/s²

Explanation:

Given that:

Initial Velocity (u) = 18.6 m/s

Time, t = 0.582

S, distance = 12 m

S = ut + 0.5at²

12 = (18.6 * 0.582) + 0.5(a)(0.582²)

12 = 10.8252 + 0.169362a

12 - 10.8252 = 0.169362a

1.1748 = 0.169362a

a = 1.1748 / 0.169362

a = 6.9366209

a = 6.94 m/s²

Hence, acceliofbthe car should be 6.94 m/s²

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

powerful computers now, not then