Calculate the parallel component of the weight of the object on the inclined plane below. 1. 0.87 N
2. 4.33 N
3. 24.5 N
4. 42.4 N

4. Wx = 42.47[N]

Explanation:

In order to solve this problem, we must first make a free body diagram, of the forces acting on the body in the inclined plane.

As we can see in the attached image, the component of the weight parallel to the surface of the inclined plane can be obtained by the sine of the angle.

i think the answer is tomato juice? not entirely sure though

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j