Hi I need help with this question (see image) . Please show workings.

Aproton is projected toward a fixed nucleus of charge +ze with velocity vo. initially the two particles are very far apart. when the proton is a distance r from the nucleus its velocity has decreased to 1/2vo. how far from the nucleus will the proton be when its velocity has dropped to 1/4vo?

If the force applied to an object remains constant, is more power needed for the object to move faster ? explain

State the following: boyle's law and charle's law