Let's say you got tired and you are now pushing with a force of 36 N. Find the acceleration of the box.

This question is incomplete, the complete question is;

A 13 kg box rests on the flat surface. The coefficient of static friction and coefficient of kinetic friction is μ_s = 0.450 and μ_k = 0.380 respectively.

Let's say you got tired and you are now pushing with a force of 36 N. Find the acceleration of the box.

the acceleration of the box is 0.9548 m/s²    {backward}

Explanation:

Given that;

mass m = 13 kg

pushing the box with a force of 36 N

the acceleration of the box = ?

ones the box starts moving, kinetic frictional force starts acting.

so

f_k = μ_k × m × g

we substitute

f_k = 0.380 × 13 × 9.8

f_k = 48.412 N

force needed to keep it in motion is 48.412 N

so

Acceleration = Net Force / mass

Acceleration = (48.412 N - 36 N) / 13

Acceleration = 12.412 / 13

Acceleration = 0.9548 m/s²    {backward}

Therefore, the acceleration of the box is 0.9548 m/s²   {backward}

50 inches should be the resultant vector