A cat is moving at 18 m/s when it accelerates at 4 m/s2 for 2 seconds. What is his new velocity? (Show which kinematic equation you used, along with your
answer)

26m/s

Explanation:

Given parameters:

Initial velocity  = 18m/s

Time  = 2s

Acceleration  = 4m/s²

Unknown:

Final velocity

Solution:

To solve this problem, we use the expression below:

     Acceleration  =

v is the final velocity

u is the initial velocity

 t is the time taken

    4   =    

      v - 18  = 8

       v  = 8 + 18 = 26m/s

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

i don't understand. explain it clearly