Physics, 11.01.2021 20:40 snowprincess99447

a 1.0kg water balloon falls downward and experiences a 4.9n air resistance as it approaches the ground. What is the acceleration of the water ballon when it experiences this air resistance

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Answer from: lildee16lildee

The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².

What is acceleration?

Acceleration is the rate of change of velocity.

To calculate the acceleration of the ballon when it experiences the air resistance, we use the formula below.

Formula:

ma = mg-F' Equation 1

Where:

m = mass of the ballon'a = acceleration of the ballonF' = air resistanceg = acceleration due to gravity.

Make a the subject of the equation

a = (mg-F')/m Equation 2

From the question,

Given:

m = 1 kgF' = 4.9 Ng = 9.8 m/s²

Substitute these values into equation 2

a = [(9.8×1)-4.9)/1a = (9.8-4.9)/1a = 4.9/1a = 4.9 m/s²

Hence, The acceleration of the balloon when it experiences the air resistance is 4.9 m/s².

Learn more about acceleration here: link

Answer from: gabrielbergemancat

Given that,

Mass of a water balloon, m = 1 kg

It comes downward an experience a 4.9 N air resistance as it approaches the ground.

To find,

The acceleration of the water balloon when it experiences this air resistance.

Solution,

Let the acceleration be a.

The net force acting on it will be :

$F_{net}=mg+F_r\\\\=1\times 10+(-4.9)\\\\=5.1\ N$

The force is also given by :

F = ma

$a=\dfrac{F}{m}\\\\a=\dfrac{5.1}{1}\\\\=5.1\ m/s^2$

So, the acceleration of the water balloon is $5.1\ m/s^2$ .

Answer from: Quest

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Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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