95 POINTS PLEASE HELP SIMPLE QUESTION A student and the waxed skis she is wearing

have a combined weight of 850 newtons.

The skier travels down a snow-covered hill

and then glides to the east across a snow-covered, horizontal surface.

2. Determine the magnitude of the normal force exerted

by the snow on the skis as the skier glides across the

horizontal surface.

3. Calculate the magnitude of the force of friction acting on the skis as the skier glides across the snowcovered, horizontal surface. [Show all work, including

the equation and substitution with units.]

I already know 2 is 850. But how do you get the coefficient of friction for 3. brainliest to best answer!

Given that,

Combined weight of a student and the waxed skis, W = 850 N

It should be given that the coefficient of friction is 0.05.

To find,

The magnitude of the normal force exerted and the magnitude of the force of friction.

Solution,

Normal force = weight of the object,

Here, weight = 850 N

Normal force = 850 N

Let f is the force of friction. It can be calculated as follows :

Hence, the normal force is 850 N and the magnitude of the force of friction is 850 N.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer