In incline plane makes an angle of 40° with the horizontal a body weighing 4000 N initial at rest moves down the slope calculate the distance travelled by the body in 5 seconds if the force of friction is 1500N

45.375m

Explanation:

To get the distance travelled by the body we will use the equation of motion

S = ut + 1/2at²

u is the initial speed = 0m/s

a is the acceleration

t is the time = 5 seconds

We need to get the acceleration first:

According to Newton's second law,

Fm is the moving force = Wsin theta

Ff is the frictional force = 1500N

m is the mass = W/g

m = 4000/9.8

m = 408.16kg

Substitute the given values in the formula and get the acceleration:

Get the required distance:

Recall that S = ut+1/2at²

S = 0(5) + 1/2*3.63*5²

S = 0+0.5*3.63*25

S = 45.375m

Hence the distance travelled by the body in 5 seconds if the force of friction is 1500N is 45.375m

an ion is a charged atom or molecule. it is charged because the number of electrons do not equal the number of protons in the atom or molecule. an atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr