HELP PLSSS A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)
ps( its not 0.242)

Given :

A 13.3 kg box sliding across the ground  decelerates at 2.42 m/s².

To Find :

The coefficient of kinetic friction.

Solution :

Frictional force applied to the box is :

   ....1)

Also, force of friction is given by :

 ....2)

Equating equation 1) and 2), we get :

Therefore, the coefficient of kinetic friction is 0.247 .

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up