Help lol! a humpback whale was 8,640 meters north of Billet Bay, swimming south at a constant velocity. If it swam one-third of the distance to the bay in 12 minutes, what was the whale's
velocity?

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Answerit is comparative because this experiment is comparing the results of the volume at minimal pressure and then increases it; ; ;