Carry out these steps, and record your findings in the table. Pour water to the 2.0 mL mark in the graduated cylinder. If you look at the graduated cylinder from the side, you will see the water forms a curve. Make sure the bottom of the curve is at the 2.0 mL mark.
Use the gram scale to measure the mass of the graduated cylinder and 2.0 mL of water. Record the mass in the table. Calculate the mass of 2.0 mL of water by subtracting the mass of the graduated cylinder.
Repeat this process to find and record the mass of 4.0 mL of water and then 6.0 mL of water.
Density is mass in grams divided by volume in cubic centimeters (cm3). 1 mL is equal to 1 cm3. Calculate and record the density of water.

heres are my answer

Explanation:

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s