Suppose you push a hockey puck of mass m across frictionless ice for a time δt, starting from rest, giving the puck speed v after traveling distance d. if you repeat the experiment with a puck of mass 2m, how long will you have to push for the puck to reach the same speed v?

Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration,

From the equation of motion,

......(1)

In the second case, when mass is 2m, then acceleration,

and t' is the time taken.

The final speed is v,

using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards