A car travelled a distance of 5km due East, then 5km due North and then 5km due East. Calculate the total distance and displacement travelled by car also sketch the path.

Total displacement

The displacement of the car is 10 kilometers due East and 5 kilometers due North.

The magnitude of the displacement of the car is approximately 11.180 kilometers.

Total distance

The total distance of the car is 15 kilometers.

Explanation:

According to the statement the car shows the following path, whose displacement is represented by the following formula: (All distances are measured in kilometers)

(1)

Where:

- First displacement to the east.

- Displacement to the north.

- Second displacement to the east.

If we know that , and , then the displacement of the car is:

The displacement of the car is 10 kilometers due East and 5 kilometers due North.

The magnitude of the displacement represents the distance of the car from point of departure in a straight line and is determined by the Pythagorean Theorem:

The magnitude of the displacement of the car is approximately 11.180 kilometers.

The distance travelled of the car is the sum of magnitudes of the displacement of the car, each of them are calculated by Pyhtagorean Theorem:

(2)

The total distance of the car is 15 kilometers.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.